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Popular Functions >

extreme f(x)=2x^2+5x-1

Solution

extreme points

f (x) = 2 x^{2} + 5 x - 1

Solution

Minimum (- \frac{5}{4}, - \frac{33}{8})

Solution steps

f^{'} (x) = 4 x + 5

Find intervals:

Decreasing

: - \infty < x < - \frac{5}{4},

Increasing

: - \frac{5}{4} < x < \infty

Plug

x = - \frac{5}{4}

into

2 x^{2} + 5 x - 1 : - \frac{33}{8}

Minimum (- \frac{5}{4}, - \frac{33}{8})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+5x-1 ?
The extreme f(x)=2x^2+5x-1 is Minimum(-5/4 ,-33/8)