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Popular Functions >

extreme f(x)=x^2-5x+2

Solution

extreme points

f (x) = x^{2} - 5 x + 2

Solution

Minimum (\frac{5}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{2},

Increasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

x^{2} - 5 x + 2 : - \frac{17}{4}

Minimum (\frac{5}{2}, - \frac{17}{4})

Graph

Popular Examples

extreme f(x)=-12x-6

extreme f(x,y)=(x^2-5y^2)e^x

extreme f(x)=(x^2)/(x^2-16)

extreme f(x,y)=x^3+y^2-2xy+7x-8y+2

extreme f(x)=(x^2+11)(9-x^2)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-5x+2 ?
The extreme f(x)=x^2-5x+2 is Minimum(5/2 ,-17/4)