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midpoint
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perpendicular 5x-6y=4,(3,9)perpendicular line (0.08,0.382),(0.16,0.609)line f(x)=ln(ln(x))inverse of f(x)=2+sqrt(2x-4)inverse inverse of f(x)=-x^2+7inverse
Frequently Asked Questions (FAQ)
What is the midpoint (-3,1),(1,-4) ?
The midpoint (-3,1),(1,-4) is (-1,-3/2)