What is the perpendicular 5x-6y=4,(3,9) ?

The perpendicular 5x-6y=4,(3,9) is y=-6/5 x+63/5

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perpendicular 5x-6y=4,(3,9)

perpendicular

5 x - 6 y = 4, (3, 9)

y = - \frac{6}{5} x + \frac{63}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

5 x - 6 y = 4

that passes through

(3, 9)

Find the slope of

5 x - 6 y = 4 : m = \frac{5}{6}

Compute the slope of the perpendicular line:

m_{p} = - \frac{6}{5}

Find the line with slope m=

- \frac{6}{5}

and passing through

(3, 9) : y = - \frac{6}{5} x + \frac{63}{5}

y = - \frac{6}{5} x + \frac{63}{5}

(0.08, 0.382), (0.16, 0.609)

f (x) = ln (ln (x))

f (x) = 2 + 2 x - 4

f (x) = - x^{2} + 7

y = - 5 x + 1

What is the perpendicular 5x-6y=4,(3,9) ?
The perpendicular 5x-6y=4,(3,9) is y=-6/5 x+63/5