What is the extreme f(x)=x^3ln(x),x>0 ?

The extreme f(x)=x^3ln(x),x>0 is Minimum(1/(\sqrt[3]{e)},-1/(3e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3ln(x),x>0

extreme points

f (x) = x^{3} ln (x), x > 0

Solution steps

Find the critical points:

Domain of

x^{3} ln (x), x > 0 : x > 0

Find intervals:

Decreasing

Increasing

Plug the extreme point

into

x^{3} ln (x) \Rightarrow y = - \frac{1}{3 e}

What is the extreme f(x)=x^3ln(x),x>0 ?
The extreme f(x)=x^3ln(x),x>0 is Minimum(1/(\sqrt[3]{e)},-1/(3e))