What is the extreme f(x)=x^3-12x-8 ?

The extreme f(x)=x^3-12x-8 is Maximum(-2,8),Minimum(2,-24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3-12x-8

extreme points

f (x) = x^{3} - 12 x - 8

Maximum (- 2, 8), Minimum (2, - 24)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x - 8 : 8

Maximum (- 2, 8)

Plug

x = 2

into

x^{3} - 12 x - 8 : - 24

Minimum (2, - 24)

Maximum (- 2, 8), Minimum (2, - 24)

What is the extreme f(x)=x^3-12x-8 ?
The extreme f(x)=x^3-12x-8 is Maximum(-2,8),Minimum(2,-24)