What is the extreme f(x)=-x^3-9x^2-24x+2 ?

The extreme f(x)=-x^3-9x^2-24x+2 is Minimum(-4,18),Maximum(-2,22)

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extreme f(x)=-x^3-9x^2-24x+2

extreme points

f (x) = - x^{3} - 9 x^{2} - 24 x + 2

Minimum (- 4, 18), Maximum (- 2, 22)

Solution steps

f^{'} (x) = - 3 x^{2} - 18 x - 24

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < - 2,

Decreasing

: - 2 < x < \infty

Plug

x = - 4

into

- x^{3} - 9 x^{2} - 24 x + 2 : 18

Minimum (- 4, 18)

Plug

x = - 2

into

- x^{3} - 9 x^{2} - 24 x + 2 : 22

Maximum (- 2, 22)

Minimum (- 4, 18), Maximum (- 2, 22)

What is the extreme f(x)=-x^3-9x^2-24x+2 ?
The extreme f(x)=-x^3-9x^2-24x+2 is Minimum(-4,18),Maximum(-2,22)