What is the inverse of f(x)=((4x-1))/((2x+3)) ?

The inverse of f(x)=((4x-1))/((2x+3)) is (-1-3x)/(2(-2+x))

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inverse of f(x)=((4x-1))/((2x+3))

inverse

f (x) = \frac{( 4 x - 1 )}{( 2 x + 3 )}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 1}{2 x + 3}

Replace

x

with

y

x = \frac{4 y - 1}{2 y + 3}

Solve for

y, x = \frac{4 y - 1}{2 y + 3}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

(x - 4)^{3}

60 x^{2} - 20 x^{3}

f (x) = \frac{1 + 2 x}{x}

4 - z^{2}

\frac{x ^{3} + 7 x ^{2} + 12 x}{x ^{3} + x ^{2} - 2 x}

What is the inverse of f(x)=((4x-1))/((2x+3)) ?
The inverse of f(x)=((4x-1))/((2x+3)) is (-1-3x)/(2(-2+x))