What is the extreme f(x)=(x^2-24)/(x-5) ?

The extreme f(x)=(x^2-24)/(x-5) is Maximum(4,8),Minimum(6,12)

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extreme f(x)=(x^2-24)/(x-5)

extreme points

f (x) = \frac{x ^{2} - 24}{x - 5}

Maximum (4, 8), Minimum (6, 12)

Solution steps

f^{'} (x) = \frac{x ^{2} - 10 x + 24}{( x - 5 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < 5,

Decreasing

: 5 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 4

into

\frac{x ^{2} - 24}{x - 5} : 8

Maximum (4, 8)

Plug

x = 6

into

\frac{x ^{2} - 24}{x - 5} : 12

Minimum (6, 12)

Maximum (4, 8), Minimum (6, 12)

What is the extreme f(x)=(x^2-24)/(x-5) ?
The extreme f(x)=(x^2-24)/(x-5) is Maximum(4,8),Minimum(6,12)