What is the extreme f(x)=x^4-8x^3+5 ?

The extreme f(x)=x^4-8x^3+5 is Saddle(0,5),Minimum(6,-427)

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extreme f(x)=x^4-8x^3+5

extreme points

f (x) = x^{4} - 8 x^{3} + 5

Saddle (0, 5), Minimum (6, - 427)

Solution steps

f^{'} (x) = 4 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{4} - 8 x^{3} + 5 : 5

Saddle (0, 5)

Plug

x = 6

into

x^{4} - 8 x^{3} + 5 : - 427

Minimum (6, - 427)

Saddle (0, 5), Minimum (6, - 427)

What is the extreme f(x)=x^4-8x^3+5 ?
The extreme f(x)=x^4-8x^3+5 is Saddle(0,5),Minimum(6,-427)