What is the extreme f(x)=xsqrt(15-x) ?

The extreme f(x)=xsqrt(15-x) is Maximum(10,10sqrt(5)),Minimum(15,0)

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extreme f(x)=xsqrt(15-x)

extreme points

f (x) = x 15 - x

Maximum (10, 105), Minimum (15, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 10 )}{2 15 - x}

Find intervals:

Increasing

: - \infty < x < 10,

Decreasing

: 10 < x < 15

Plug

x = 10

into

x 15 - x : 105

Maximum (10, 105)

Plug

x = 15

into

x 15 - x : 0

Minimum (15, 0)

Maximum (10, 105), Minimum (15, 0)

What is the extreme f(x)=xsqrt(15-x) ?
The extreme f(x)=xsqrt(15-x) is Maximum(10,10sqrt(5)),Minimum(15,0)