What is the inverse of f(x)=(x^2-9)/(8x^2) ?

The inverse of f(x)=(x^2-9)/(8x^2) is sqrt(-9/(8x-1)),-sqrt(-9/(8x-1))

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inverse of f(x)=(x^2-9)/(8x^2)

inverse

f (x) = \frac{x ^{2} - 9}{8 x ^{2}}

- \frac{9}{8 x - 1}, - - \frac{9}{8 x - 1}

Solution steps

y = \frac{x ^{2} - 9}{8 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 9}{8 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 9}{8 y ^{2}}

- \frac{9}{8 x - 1}, - - \frac{9}{8 x - 1}

\frac{x + 1}{2 x + 1}

x^{3} + 8 x

f (x) = - \frac{2 - x ^{2}}{3}

f (x) = \frac{x ^{2}}{x ^{2} - 1}

- x + 3 y + 5 = 0

What is the inverse of f(x)=(x^2-9)/(8x^2) ?
The inverse of f(x)=(x^2-9)/(8x^2) is sqrt(-9/(8x-1)),-sqrt(-9/(8x-1))