What is the inverse of f(x)=-sqrt((2-x^2)/3) ?

The inverse of f(x)=-sqrt((2-x^2)/3) is sqrt(-3x^2+2),-sqrt(-3x^2+2)

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inverse of f(x)=-sqrt((2-x^2)/3)

inverse

f (x) = - \frac{2 - x ^{2}}{3}

- 3 x^{2} + 2, - - 3 x^{2} + 2

Solution steps

y = - \frac{2 - x ^{2}}{3}

Replace

x

with

y

x = - \frac{2 - y ^{2}}{3}

Solve for

y, x = - \frac{2 - y ^{2}}{3}

- 3 x^{2} + 2, - - 3 x^{2} + 2

f (x) = \frac{x ^{2}}{x ^{2} - 1}

- x + 3 y + 5 = 0

12 x^{2} - 64

2 x^{4} - 12 x^{2}

f (x) = \frac{∣ x ∣}{x ^{2} + 1}

What is the inverse of f(x)=-sqrt((2-x^2)/3) ?
The inverse of f(x)=-sqrt((2-x^2)/3) is sqrt(-3x^2+2),-sqrt(-3x^2+2)