What is the domain of f(x)=(sqrt(x-2))/(x^2-16) ?

The domain of f(x)=(sqrt(x-2))/(x^2-16) is 2 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=(sqrt(x-2))/(x^2-16)

domain

f (x) = \frac{x - 2}{x ^{2} - 16}

2 \leq x < 4 or x > 4

Interval Notation

[2, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

2 \leq x < 4 or x > 4

What is the domain of f(x)=(sqrt(x-2))/(x^2-16) ?
The domain of f(x)=(sqrt(x-2))/(x^2-16) is 2<= x<4\lor x>4