What is the domain of f(r)=arcsec(6r^2-5r-5) ?

The domain of f(r)=arcsec(6r^2-5r-5) is r = 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(r)=arcsec(6r^2-5r-5)

domain

f (r) = arcsec (6 r^{2} - 5 r - 5)

r \leq - \frac{2}{3} or - \frac{1}{2} \leq r \leq \frac{4}{3} or r \geq \frac{3}{2}

Interval Notation

(- \infty, - \frac{2}{3}] \cup [- \frac{1}{2}, \frac{4}{3}] \cup [\frac{3}{2}, \infty)

Solution steps

Find known functions domain restrictions:

r \leq - \frac{2}{3} or - \frac{1}{2} \leq r \leq \frac{4}{3} or r \geq \frac{3}{2}

The function domain

r \leq - \frac{2}{3} or - \frac{1}{2} \leq r \leq \frac{4}{3} or r \geq \frac{3}{2}

What is the domain of f(r)=arcsec(6r^2-5r-5) ?
The domain of f(r)=arcsec(6r^2-5r-5) is r<=-2/3 \lor-1/2 <= r<= 4/3 \lor r>= 3/2