What is the domain of f(x)= 1/(sqrt(4-t^2)) ?

The domain of f(x)= 1/(sqrt(4-t^2)) is -2<t<2

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domain of f(x)= 1/(sqrt(4-t^2))

domain

f (x) = \frac{1}{4 - t ^{2}}

- 2 < t < 2

Interval Notation

(- 2, 2)

Solution steps

Find non-negative values for radicals:

- 2 \leq t \leq 2

Find undefined (singularity) points:

t = 2, t = - 2

Combine real regions and undefined points for final function domain

- 2 < t < 2

What is the domain of f(x)= 1/(sqrt(4-t^2)) ?
The domain of f(x)= 1/(sqrt(4-t^2)) is -2<t<2