What is the domain of f(x)=((x+6)^2)/(sqrt(8x-7)) ?

The domain of f(x)=((x+6)^2)/(sqrt(8x-7)) is x> 7/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=((x+6)^2)/(sqrt(8x-7))

domain

f (x) = \frac{( x + 6 ) ^{2}}{8 x - 7}

x > \frac{7}{8}

Interval Notation

(\frac{7}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{7}{8}

Find undefined (singularity) points:

x = \frac{7}{8}

Combine real regions and undefined points for final function domain

x > \frac{7}{8}

What is the domain of f(x)=((x+6)^2)/(sqrt(8x-7)) ?
The domain of f(x)=((x+6)^2)/(sqrt(8x-7)) is x> 7/8