What is the inverse of f(x)=3x^2+7 ?

The inverse of f(x)=3x^2+7 is sqrt((x-7)/3),-sqrt((x-7)/3)

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inverse of f(x)=3x^2+7

inverse

f (x) = 3 x^{2} + 7

\frac{x - 7}{3}, - \frac{x - 7}{3}

Solution steps

y = 3 x^{2} + 7

Replace

x

with

y

x = 3 y^{2} + 7

Solve for

y, x = 3 y^{2} + 7

\frac{x - 7}{3}, - \frac{x - 7}{3}

y = - 5 x + 2

\frac{6 - 1}{4 - 2}

f (x) = 5^{3 x - 5}

f (x) = 2 - 1 - x^{2}

f (x) = - 2 x^{2} + 8 x - 5

What is the inverse of f(x)=3x^2+7 ?
The inverse of f(x)=3x^2+7 is sqrt((x-7)/3),-sqrt((x-7)/3)