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Popular Functions >

range of f(x)=-2x^2+8x-5

Solution

range

Solution

f (x) \leq 3

+1

Interval Notation

Solution steps

Vertex of

- 2 x^{2} + 8 x - 5 :

Maximum

(2, 3)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (2, 3)

f (x) \leq 3

Graph

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domain of f(x)=(x+2)/(x^2-4x+4)

Frequently Asked Questions (FAQ)

What is the range of f(x)=-2x^2+8x-5 ?
The range of f(x)=-2x^2+8x-5 is f(x)<= 3