What is the critical x^8(x-1)^7 ?

The critical x^8(x-1)^7 is x=0,x= 8/15 ,x=1

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critical x^8(x-1)^7

critical points

x^{8} (x - 1)^{7}

x = 0, x = \frac{8}{15}, x = 1

Solution steps

x^{8} (x - 1)^{7}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{8}{15}, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{8} (x - 1)^{7} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{8}{15}, x = 1

sin (2 x), 0 \leq x \leq 2 π

x = - 5

(x - 2)^{2} - 1

f (x) = \frac{2 - x ^{2}}{x ^{2} + 6 x - 40}

g (x) = - x + 1