What is the inflection f(x)=0.2x^2+1/(2x) ?

The inflection f(x)=0.2x^2+1/(2x) is (-\sqrt[3]{5/2},-8.0E-17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inflection f(x)=0.2x^2+1/(2x)

inflection

(- 3 \frac{5}{2}, - 8.0 E - 17)

Solution steps

Find where

f^{''} (x)

is equal to zero or undefined

x = - 3 \frac{5}{2}, x = 0

Identify inflection points not in domain or where

f (x)

is not continuous

Domain of

0.2 x^{2} + \frac{1}{2 x} : x < 0 or x > 0

f (x)

is not defined at

x = 0

, therefore:

x = - 3 \frac{5}{2}

Find intervals:

Concave Upward

: - \infty < x < - 3 \frac{5}{2},

Concave Downward

: - 3 \frac{5}{2} < x < 0,

Concave Upward

: 0 < x < \infty

Plug

x = - 3 \frac{5}{2}

into

0.2 x^{2} + \frac{1}{2 x} : - 8.0 E - 17

(- 3 \frac{5}{2}, - 8.0 E - 17)

What is the inflection f(x)=0.2x^2+1/(2x) ?
The inflection f(x)=0.2x^2+1/(2x) is (-\sqrt[3]{5/2},-8.0E-17)