What is the domain of \sqrt[3]{x+12} ?

The domain of \sqrt[3]{x+12} is -infinity <x<infinity

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domain of \sqrt[3]{x+12}

domain

3 x + 12

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

(- 6, 1), (1, 8)

f (x) = \frac{4 x + 9}{7 x}

f (x) = 2 x^{5} + x^{7}

- \frac{1}{5} 3^{x} - 2

f (x) = (5 x - 7)^{2} - 13

What is the domain of \sqrt[3]{x+12} ?
The domain of \sqrt[3]{x+12} is -infinity <x<infinity