en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of-x^2+9

Solution

range

- x^{2} + 9

Solution

f (x) \leq 9

+1

Interval Notation

(- \infty, 9]

Solution steps

Vertex of

- x^{2} + 9 :

Maximum

(0, 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 9)

f (x) \leq 9

Popular Examples

global 16x^3-x^4 global extreme points

16 x^{3} - x^{4}

intercepts of f(x)=(x-1)/(x+4)intercepts

f (x) = \frac{x - 1}{x + 4}

distance (-4,3),(4,-2)distance

(- 4, 3), (4, - 2)

extreme f(x)=x^3+3x^2-4 extreme points

f (x) = x^{3} + 3 x^{2} - 4

inflection f(x)=0.2x^2+1/(2x)inflection points

f (x) = 0.2 x^{2} + \frac{1}{2 x}

Frequently Asked Questions (FAQ)

What is the range of-x^2+9 ?
The range of-x^2+9 is f(x)<= 9