What is the domain of f(x)=sqrt(2x+3)-4 ?

The domain of f(x)=sqrt(2x+3)-4 is x>=-3/2

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domain of f(x)=sqrt(2x+3)-4

domain

f (x) = 2 x + 3 - 4

x \geq - \frac{3}{2}

Interval Notation

[- \frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{2}

The function domain

x \geq - \frac{3}{2}

f (x) = \frac{( x ^{2} - 16 )}{x ^{2} - 6 x + 8}

f (x) = 9 - x^{2} + x + 3

f (x) = \frac{- 16 + 9 x}{4}

y = 10 + \frac{10}{4 x + 12}

f (x) = 3 x + 8

What is the domain of f(x)=sqrt(2x+3)-4 ?
The domain of f(x)=sqrt(2x+3)-4 is x>=-3/2