What is the domain of f(x)=sqrt(9-x^2)+sqrt(x+3) ?

The domain of f(x)=sqrt(9-x^2)+sqrt(x+3) is -3<= x<= 3

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domain of f(x)=sqrt(9-x^2)+sqrt(x+3)

domain

f (x) = 9 - x^{2} + x + 3

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

f (x) = \frac{- 16 + 9 x}{4}

y = 10 + \frac{10}{4 x + 12}

f (x) = 3 x + 8

f (x) = 3 (x - 4)

f (x) = 6 x + 6

What is the domain of f(x)=sqrt(9-x^2)+sqrt(x+3) ?
The domain of f(x)=sqrt(9-x^2)+sqrt(x+3) is -3<= x<= 3