What is the domain of log_{2}(3*2^{x+1}-64) ?

The domain of log_{2}(3*2^{x+1}-64) is x>(ln(64/3))/(ln(2))-1

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domain of log_{2}(3*2^{x+1}-64)

domain

lo g_{2} (3 \cdot 2^{x + 1} - 64)

x > \frac{ln ( \frac{64}{3} )}{ln ( 2 )} - 1

Interval Notation

(\frac{ln ( \frac{64}{3} )}{ln ( 2 )} - 1, \infty)

Solution steps

Find positive values for logs:

x > - lo g_{2} (3) + 5

The function domain

x > \frac{ln ( \frac{64}{3} )}{ln ( 2 )} - 1

What is the domain of log_{2}(3*2^{x+1}-64) ?
The domain of log_{2}(3*2^{x+1}-64) is x>(ln(64/3))/(ln(2))-1