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midpoint
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line (8,-31),(5,-19)inverse of f(x)=\sqrt[3]{-x-1}asymptotes of f(x)=(x-4)/(-4x-16)domain of f(x)=(x^2-1)/(3x+9)symmetry y=(4x^2+1)/(2x)
Frequently Asked Questions (FAQ)
What is the midpoint (9,-9),(-4,5) ?
The midpoint (9,-9),(-4,5) is (5/2 ,-2)