What is the extreme f(x)=x+(16)/x ?

The extreme f(x)=x+(16)/x is Maximum(-4,-8),Minimum(4,8)

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extreme f(x)=x+(16)/x

extreme points

f (x) = x + \frac{16}{x}

Maximum (- 4, - 8), Minimum (4, 8)

Solution steps

f^{'} (x) = 1 - \frac{16}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

x + \frac{16}{x} : - 8

Maximum (- 4, - 8)

Plug

x = 4

into

x + \frac{16}{x} : 8

Minimum (4, 8)

Maximum (- 4, - 8), Minimum (4, 8)

y = ln (3 x)

f (x) = \frac{2 - x}{x ^{2} + 4 x}

f (x) = ln (x)

f (x) = 6 cos (3 x + \frac{π}{2})

f (x) = 0.55 \cdot x - 2.8 e^{5}

What is the extreme f(x)=x+(16)/x ?
The extreme f(x)=x+(16)/x is Maximum(-4,-8),Minimum(4,8)