What is the domain of f(x)=(sqrt(2-x))/(x^2+4x) ?

The domain of f(x)=(sqrt(2-x))/(x^2+4x) is x<-4\lor-4<x<0\lor 0<x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(2-x))/(x^2+4x)

domain

f (x) = \frac{2 - x}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or 0 < x \leq 2

Solution steps

Find non-negative values for radicals:

x \leq 2

Find undefined (singularity) points:

x = 0, x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or - 4 < x < 0 or 0 < x \leq 2

f (x) = ln (x)

f (x) = 6 cos (3 x + \frac{π}{2})

f (x) = 0.55 \cdot x - 2.8 e^{5}

f (x) = 2^{\frac{x}{2}}

(0, 4), (- 3, 0)

What is the domain of f(x)=(sqrt(2-x))/(x^2+4x) ?
The domain of f(x)=(sqrt(2-x))/(x^2+4x) is x<-4\lor-4<x<0\lor 0<x<= 2