What is the inverse of f(x)=1+\sqrt[3]{x-2} ?

The inverse of f(x)=1+\sqrt[3]{x-2} is x^3-3x^2+3x+1

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inverse of f(x)=1+\sqrt[3]{x-2}

inverse

x^{3} - 3 x^{2} + 3 x + 1

Solution steps

Replace

x

with

y

Solve for

x^{3} - 3 x^{2} + 3 x + 1

f (x) = \frac{- 2 x - 9}{4 x - 19}

y = 8 x - 13, (2, 3)

f (x) = \frac{( x + 3 )}{x ^{2} - 4 x + 3}

f (x) = x e^{x}

f (x) = - x^{4} - 5 x^{3} + 7 x - 3

What is the inverse of f(x)=1+\sqrt[3]{x-2} ?
The inverse of f(x)=1+\sqrt[3]{x-2} is x^3-3x^2+3x+1