What is the perpendicular y=8x-13,(2,3) ?

The perpendicular y=8x-13,(2,3) is y=-1/8 x+13/4

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perpendicular y=8x-13,(2,3)

perpendicular

y = 8 x - 13, (2, 3)

y = - \frac{1}{8} x + \frac{13}{4}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 8 x - 13

that passes through

(2, 3)

Find the slope of

y = 8 x - 13 : m = 8

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(2, 3) : y = - \frac{1}{8} x + \frac{13}{4}

y = - \frac{1}{8} x + \frac{13}{4}

f (x) = \frac{( x + 3 )}{x ^{2} - 4 x + 3}

f (x) = x e^{x}

f (x) = - x^{4} - 5 x^{3} + 7 x - 3

sin (x)

What is the perpendicular y=8x-13,(2,3) ?
The perpendicular y=8x-13,(2,3) is y=-1/8 x+13/4