What is the inflection f(x)=x^4-32x^2+9 ?

The inflection f(x)=x^4-32x^2+9 is (-4/(sqrt(3)),-1199/9),(4/(sqrt(3)),-1199/9)

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inflection f(x)=x^4-32x^2+9

inflection points

f (x) = x^{4} - 32 x^{2} + 9

(- \frac{4}{3}, - \frac{1199}{9}), (\frac{4}{3}, - \frac{1199}{9})

Solution steps

f^{''} (x) = 12 x^{2} - 64

Find intervals:

Concave Upward

: - \infty < x < - \frac{4}{3},

Concave Downward

: - \frac{4}{3} < x < \frac{4}{3},

Concave Upward

: \frac{4}{3} < x < \infty

Plug

x = - \frac{4}{3}

into

x^{4} - 32 x^{2} + 9 : - \frac{1199}{9}

(- \frac{4}{3}, - \frac{1199}{9})

Plug

x = \frac{4}{3}

into

x^{4} - 32 x^{2} + 9 : - \frac{1199}{9}

(\frac{4}{3}, - \frac{1199}{9})

(- \frac{4}{3}, - \frac{1199}{9}), (\frac{4}{3}, - \frac{1199}{9})

3 x - 2 y = - 6

f (x) = \frac{y}{y - 6} + \frac{15}{y + 6}

f (x) = \frac{- 15}{x ^{2} + 5}

y = x + 4, (- 1, 2)

f (x) = \frac{x + 5}{x - 3}

What is the inflection f(x)=x^4-32x^2+9 ?
The inflection f(x)=x^4-32x^2+9 is (-4/(sqrt(3)),-1199/9),(4/(sqrt(3)),-1199/9)