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Popular >

extreme f(x)=(-15)/(x^2+5)

Solution

extreme points

f (x) = \frac{- 15}{x ^{2} + 5}

Solution

Minimum (0, - 3)

Solution steps

f^{'} (x) = \frac{30 x}{( x ^{2} + 5 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{- 15}{x ^{2} + 5} : - 3

Minimum (0, - 3)

Popular Examples

parallel y=x+4,(-1,2)parallel

y = x + 4, (- 1, 2)

domain of f(x)=(sqrt(x+5))/(x-3)domain

f (x) = \frac{x + 5}{x - 3}

midpoint (2,4),(1,-3)midpoint

(2, 4), (1, - 3)

domain of f(x)= 3/(3/x)domain

f (x) = \frac{3}{\frac{3}{x}}

slope of y-3=3(x+1)slope

y - 3 = 3 (x + 1)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-15)/(x^2+5) ?
The extreme f(x)=(-15)/(x^2+5) is Minimum(0,-3)