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midpoint
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domain of f(x)=sqrt(2x-12)domain of f(x)=3x^2+6xparity f(x)=arctan((x-1)/(x+1))inverse of (8x+9)/(x+8)intercepts of f(x)=x^2-4x+1
Frequently Asked Questions (FAQ)
What is the midpoint (5 1/2 ,-3 1/4),(2 1/4 ,-1 3/4) ?
The midpoint (5 1/2 ,-3 1/4),(2 1/4 ,-1 3/4) is (3/2 ,-3/4)