What is the domain of f(x)=sqrt(2x-12) ?

The domain of f(x)=sqrt(2x-12) is x>= 6

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domain of f(x)=sqrt(2x-12)

domain

f (x) = 2 x - 12

x \geq 6

Interval Notation

[6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 6

The function domain

x \geq 6

f (x) = 3 x^{2} + 6 x

f (x) = arctan (\frac{x - 1}{x + 1})

\frac{8 x + 9}{x + 8}

f (x) = x^{2} - 4 x + 1

π - 3 arcsin (2 x - 1)

What is the domain of f(x)=sqrt(2x-12) ?
The domain of f(x)=sqrt(2x-12) is x>= 6