What is the domain of f(x)=ln(1/(x+2)) ?

The domain of f(x)=ln(1/(x+2)) is x>-2

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domain of f(x)=ln(1/(x+2))

domain

f (x) = ln (\frac{1}{x + 2})

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find positive values for logs:

x > - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

f (x) = - x^{3} - 2 x^{2} - 4 x - 3

\frac{2}{1 - e ^{x}}

f (x) = \frac{4 x - 1}{2 x + 9}

y = ln (x + 5)

ln (x) + 7