What is the inverse of f(x)=(4x-1)/(2x+9) ?

The inverse of f(x)=(4x-1)/(2x+9) is (-1-9x)/(2(-2+x))

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inverse of f(x)=(4x-1)/(2x+9)

inverse

f (x) = \frac{4 x - 1}{2 x + 9}

\frac{- 1 - 9 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 1}{2 x + 9}

Replace

x

with

y

x = \frac{4 y - 1}{2 y + 9}

Solve for

y, x = \frac{4 y - 1}{2 y + 9}

\frac{- 1 - 9 x}{2 ( - 2 + x )}

y = ln (x + 5)

ln (x) + 7

\frac{( x ^{2} )}{x - 6}

f (x) = \frac{8}{x ^{2} + 4}

6 x^{4} - 7 x^{2} - 5

What is the inverse of f(x)=(4x-1)/(2x+9) ?
The inverse of f(x)=(4x-1)/(2x+9) is (-1-9x)/(2(-2+x))