What is the domain of g(x)=sqrt(x^2-9) ?

The domain of g(x)=sqrt(x^2-9) is x = 3

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domain of g(x)=sqrt(x^2-9)

domain

g (x) = x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

4 x - 2 y = 8

x^{4} - 1

f (x) = \frac{4}{x + 1}

f (x) = ln (e^{x + 1}) + ln (2) - 1

What is the domain of g(x)=sqrt(x^2-9) ?
The domain of g(x)=sqrt(x^2-9) is x<=-3\lor x>= 3