What is the range of f(x)=sqrt(x-1)+sqrt(x-2) ?

The range of f(x)=sqrt(x-1)+sqrt(x-2) is f(x)>= 1

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range of f(x)=sqrt(x-1)+sqrt(x-2)

range

f (x) = x - 1 + x - 2

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x - 1 + x - 2 : x \geq 2

Extreme Points of

x - 1 + x - 2 :

Minimum

(2, 1)

Find the range for the interval

2 \leq x < \infty : 1 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 1

x^{\frac{2}{3}} ln ∣ x ∣

- 2 (x + 2)^{2}

(- 2.1) (- 1.1)

\frac{( x - 2 )}{x ^{2} + 5 x + 4}

x + y = 4

What is the range of f(x)=sqrt(x-1)+sqrt(x-2) ?
The range of f(x)=sqrt(x-1)+sqrt(x-2) is f(x)>= 1