What is the inverse of y=5(1/8)^{x+9}-7 ?

The inverse of y=5(1/8)^{x+9}-7 is -(ln((x+7)/5))/(3ln(2))-9

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inverse of y=5(1/8)^{x+9}-7

inverse

y = 5 (\frac{1}{8})^{x + 9} - 7

- \frac{ln ( \frac{x + 7}{5} )}{3 ln ( 2 )} - 9

Solution steps

y = 5 (\frac{1}{8})^{x + 9} - 7

Replace

x

with

y

x = 5 (\frac{1}{8})^{y + 9} - 7

Solve for

y, x = 5 (\frac{1}{8})^{y + 9} - 7

- \frac{ln ( \frac{x + 7}{5} )}{3 ln ( 2 )} - 9

(x + 5) e^{- 2 x}

f (x) = \frac{x - 4}{x ^{2} - 5 x + 4}

f (x) = (x + 1)^{2} - 9

f (x) = 1 - \frac{2}{x + 3}

5 (x + 3)

What is the inverse of y=5(1/8)^{x+9}-7 ?
The inverse of y=5(1/8)^{x+9}-7 is -(ln((x+7)/5))/(3ln(2))-9