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Popular >

range of f(x)=(x+1)^2-9

Solution

range

f (x) = (x + 1)^{2} - 9

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

(x + 1)^{2} - 9 :

Minimum

(- 1, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, - 9)

f (x) \geq - 9

Popular Examples

inverse of f(x)=1-2/(sqrt(x+3))inverse

f (x) = 1 - \frac{2}{x + 3}

intercepts of 5(x+3)intercepts

5 (x + 3)

domain of x/(3x+6)domain

\frac{x}{3 x + 6}

range of sqrt(x/(x-2))range

\frac{x}{x - 2}

inverse of f(x)=-4x+2/x inverse

f (x) = - 4 x + \frac{2}{x}

Frequently Asked Questions (FAQ)

What is the range of f(x)=(x+1)^2-9 ?
The range of f(x)=(x+1)^2-9 is f(x)>=-9