What is the inverse of f(x)=2+3/(sqrt(5y-4)) ?

The inverse of f(x)=2+3/(sqrt(5y-4)) is (4y^2-16y+25)/(5(y^2-4y+4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=2+3/(sqrt(5y-4))

inverse

\frac{4 y ^{2} - 16 y + 25}{5 ( y ^{2} - 4 y + 4 )}

Solution steps

x = 2 + \frac{3}{5 y - 4}

Replace

y

with

x

y = 2 + \frac{3}{5 x - 4}

Solve for

x, y = 2 + \frac{3}{5 x - 4}

\frac{4 y ^{2} - 16 y + 25}{5 ( y ^{2} - 4 y + 4 )}

What is the inverse of f(x)=2+3/(sqrt(5y-4)) ?
The inverse of f(x)=2+3/(sqrt(5y-4)) is (4y^2-16y+25)/(5(y^2-4y+4))