What is the asymptotes of (2^x-8)/(4-2^x) ?

The asymptotes of (2^x-8)/(4-2^x) is Vertical: x=2,Horizontal: y=-1,y=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of (2^x-8)/(4-2^x)

asymptotes

\frac{2 ^{x} - 8}{4 - 2 ^{x}}

Vertical : x = 2, Horizontal : y = - 1, y = - 2

Solution steps

Vertical asymptotes of

\frac{2 ^{x} - 8}{4 - 2 ^{x}} : x = 2

Horizontal Asymptotes of

\frac{2 ^{x} - 8}{4 - 2 ^{x}} : y = - 1, y = - 2

Slant Asymptotes of

\frac{2 ^{x} - 8}{4 - 2 ^{x}} :

None

Vertical : x = 2, Horizontal : y = - 1, y = - 2

3 sin (x) + 3 cos (x)

\frac{5}{x ^{2} + 1}

f (x) = - \frac{1}{2} x + 4

f (x) = 5 + \frac{25}{x}

- cos (x)

What is the asymptotes of (2^x-8)/(4-2^x) ?
The asymptotes of (2^x-8)/(4-2^x) is Vertical: x=2,Horizontal: y=-1,y=-2