What is the inverse of 4(x+2)^2+5 ?

The inverse of 4(x+2)^2+5 is (sqrt(x-5))/2-2,-(sqrt(x-5))/2-2

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inverse of 4(x+2)^2+5

inverse

4 (x + 2)^{2} + 5

\frac{x - 5}{2} - 2, - \frac{x - 5}{2} - 2

Solution steps

y = 4 (x + 2)^{2} + 5

Replace

x

with

y

x = 4 (y + 2)^{2} + 5

Solve for

y, x = 4 (y + 2)^{2} + 5

\frac{x - 5}{2} - 2, - \frac{x - 5}{2} - 2

f (x) = 16 - x^{2}

x^{2} + 4 x + 4

f (x) = lo g_{3} (x + 2)

y = 0

What is the inverse of 4(x+2)^2+5 ?
The inverse of 4(x+2)^2+5 is (sqrt(x-5))/2-2,-(sqrt(x-5))/2-2