What is the inverse of f(x)=((3\sqrt[3]{x-2}-5))/7 ?

The inverse of f(x)=((3\sqrt[3]{x-2}-5))/7 is (343x^3+125}{27}+\frac{245x^2+175x)/9+2

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inverse of f(x)=((3\sqrt[3]{x-2}-5))/7

inverse

\frac{343 x ^{3} + 125}{27} + \frac{245 x ^{2} + 175 x}{9} + 2

Solution steps

y = \frac{3 3 x - 2 - 5}{7}

Replace

x

with

y

x = \frac{3 3 y - 2 - 5}{7}

Solve for

y, x = \frac{3 3 y - 2 - 5}{7}

\frac{343 x ^{3} + 125}{27} + \frac{245 x ^{2} + 175 x}{9} + 2

What is the inverse of f(x)=((3\sqrt[3]{x-2}-5))/7 ?
The inverse of f(x)=((3\sqrt[3]{x-2}-5))/7 is (343x^3+125}{27}+\frac{245x^2+175x)/9+2