What is the answer to (2x-x^2)/(3x^2+2)=0 ?

The answer to (2x-x^2)/(3x^2+2)=0 is x=0,x=2

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(2x-x^2)/(3x^2+2)=0

\frac{2 x - x ^{2}}{3 x ^{2} + 2} = 0

x = 0, x = 2

Solution steps

\frac{2 x - x ^{2}}{3 x ^{2} + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x - x^{2} = 0

Solve

2 x - x^{2} = 0 : x = 0, x = 2

x = 0, x = 2

f (x) = \frac{( \frac{x}{1 + x} )}{1 + ( \frac{x}{1 + x} )}

f (x) = \frac{x ^{2} - 1}{2 x - 3}

\frac{2 x ^{2} - 9 x + 4}{x ^{2} - 7 x + 12}

f (x) = \frac{4}{x + 7}

x^{4} - 7 x^{3}

What is the answer to (2x-x^2)/(3x^2+2)=0 ?
The answer to (2x-x^2)/(3x^2+2)=0 is x=0,x=2
Solve for x: (2x-x^2)/(3x^2+2)=0
The solution is x=0,x=2