What is the domain of f(x)=(x^2-1)/(2x-3) ?

The domain of f(x)=(x^2-1)/(2x-3) is x 3/2

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domain of f(x)=(x^2-1)/(2x-3)

domain

f (x) = \frac{x ^{2} - 1}{2 x - 3}

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}

The function domain

x < \frac{3}{2} or x > \frac{3}{2}

\frac{2 x ^{2} - 9 x + 4}{x ^{2} - 7 x + 12}

f (x) = \frac{4}{x + 7}

x^{4} - 7 x^{3}

y = x^{4} - 8 x^{2} - 9

f (x) = \frac{lo g _{10} ( 2 + x )}{x + 3}

What is the domain of f(x)=(x^2-1)/(2x-3) ?
The domain of f(x)=(x^2-1)/(2x-3) is x< 3/2 \lor x> 3/2