What is the inverse of f(x)=(x^2-5)/(7x^2) ?

The inverse of f(x)=(x^2-5)/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))

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inverse of f(x)=(x^2-5)/(7x^2)

inverse

f (x) = \frac{x ^{2} - 5}{7 x ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

Solution steps

y = \frac{x ^{2} - 5}{7 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 5}{7 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 5}{7 y ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

f (x) = \frac{1}{x ^{2} + 1}

4 sin (3 x)

y = \frac{1}{5} x + 7

f (x) = - x + 12

\frac{x ^{2} + x + 1}{x ^{2} - 7 x + 12}

What is the inverse of f(x)=(x^2-5)/(7x^2) ?
The inverse of f(x)=(x^2-5)/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))