What is the perpendicular y= 1/5 x+7 ?

The perpendicular y= 1/5 x+7 is y=-5x+b

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perpendicular y= 1/5 x+7

perpendicular

y = \frac{1}{5} x + 7

y = - 5 x + b

Solution steps

Find the slope of

y = \frac{1}{5} x + 7 : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Line with slope m=

- 5 : y = - 5 x + b

y = - 5 x + b

f (x) = - x + 12

\frac{x ^{2} + x + 1}{x ^{2} - 7 x + 12}

(- 2.6) (9)

f (x) = \frac{- 3}{- 2 x + 1}

\frac{4}{x + 3}