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Popular Functions >

range of f(x)=x^2+x-10

Solution

range

Solution

f (x) \geq - \frac{41}{4}

+1

Interval Notation

Solution steps

Vertex of

x^{2} + x - 10 :

Minimum

(- \frac{1}{2}, - \frac{41}{4})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- \frac{1}{2}, - \frac{41}{4})

f (x) \geq - \frac{41}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+x-10 ?
The range of f(x)=x^2+x-10 is f(x)>=-41/4